Hallo BI,
\(\frac { B }{ G }\) = \(\frac { b }{ g }\) = \(\frac { 2 }{ 1 }\) → b = 2g
\(\frac { 1 }{ f }\) = \(\frac { 1 }{ b }\) + \(\frac { 1 }{ g }\) = \(\frac { 1 }{ 2g }\) + \(\frac { 1 }{ g }\) = \(\frac { 1 }{ 2g }\) + \(\frac { 2 }{ 2g }\)
= \(\frac { 3 }{ 2g }\) → f = \(\frac { 2g }{ 3}\)
→ g = 3/2 * f = 75 mm [ in der Zeichnung 3,75 * 20 mm ]
[ Gegenstandsweite = Entfernung des Objekts von der Linse ]
~draw~ strecke(-10|2 0|2);;punkt(-2.5|0 "");punkt(2.5|0 "");strecke(0|-4 10|-4);strecke(0|2 7.5|-4);vektor(-3.75|0 0|2 "G");vektor(7.5|0 0|-4 "B");text(2|3.5 "1 = 20 mm");text(0.1|5.5 "Linsenmitte");text(-2.1|2.5 "g");text(4|-4.5 "b");text(2.4|0.5 "F");strecke(-3.75|2 7.5|-4);zoom(10) ~draw~
Gruß Wolfgang